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Improved Matrix II
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Bulent Epikur
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Aphrodite EPHESUS Frenzy
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RE: Improved Matrix II
Well, if the NADO would still have an strength of 8-9 for me it's no problem. I see more a problem that an alliance with a huge amount of members will become more unclear. But this will be every alliance chef's own decision how many members he will affilate.
I assume, the problem will be the "new adjustment" of the single states. Like Hessen in the first placed alliance ALPS with presently a single strength of 3,94 points
Either this strength has to be cut back of his third value, approx. to 1,31, to come to the summarized "new" fixed total ally worth of 11. Or the "formula" will be adjusted, so even if it stays by 3,94, only one third will be "used", to warranty the new "limited" ally worth of 11.
When this "Usus" should be handled for all allies in the same way , so, should the distance of the allies would stay the same. 
Or do I have misunderstand something? And all allies presently over 11 will be limited to 11?
And further I am generally afraid of that an unlimited total number of members could create bigger and stronger alliances, even this would be valid for the first 3 or 4 allies!
What I haven't understand is: Why should be a huge amount of members should create unclearness?
Angesichts dieser Nacht voller Zeichen und Sterne wurde ich zum ersten Mal empfänglich für die zärtliche Gleichgültigkeit der Welt. (...by embracing the "gentle indifference of the world")
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| 12.03.2008 19:00 |
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Sheep
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Puristan
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RE: Improved Matrix II
Hmm, there are different ways to make sure alliance strength is always between 0 and 11. The current value (before Improved Matrix II) can be used for computation, I will call it c (like current).
So easiest would be: Alliance strength = minimum of c and 11
It's just cut off at 11, so players will more or less easily reach it and then lose some motivation.
Better would be: Alliance strength = 11 * (1 - 2^(-c))
2^(- very high number) is equal to 1 / 2^(very high number), and this is very small. So 1 - 2^(- very high number) is a bit lower than 1, since only a bit is subtracted. Multiplied with 11 you arrive near 11.
ALPS has alliance strength 33.7 currently, means c = 33.7. The new alliance strength would be 11 * (1 - 2^(-33.7)) which is very very close to 11. In case it's still too easy, we can introduce a multiplier of k for c.
Alliance strength = 11 * (1 - 2^(-k*c))
For example, k could be 0.1. It should be between 0 and 1 to properly reduce alliance strength. For ALPS this means: 11 * (1 - 2^(-3.37)) = 9.936... Probably a reasonable value, probably k should be modified further.
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| 12.03.2008 20:37 |
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Z. Beeblebrox
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Atlantis
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RE: Improved Matrix II
That sounds quite good.
Malone, did you think of something like that for the new matrix?
There are I0 kind of people:
Those who understand binary
and the others.
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| 12.03.2008 22:09 |
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Malone
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Joyland Malonatia Prosperia
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RE: Improved Matrix II
Per aspera ad astra.
Please post questions always in the forum and do not message them to me!
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| 12.03.2008 22:49 |
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gottvater
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Himmelreich1 Himmelreich2 Himmelreich3
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RE: Improved Matrix II
I understood approximately half about the topic. But when (approximately) the strength reduction will take place?
Are there no more important affairs?
Nehmt die Menschen wie sie sind - andere gibt's nicht... /Take people as they are - there are no other... (K. Adenauer)
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| 12.03.2008 23:35 |
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Malone
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Joyland Malonatia Prosperia
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RE: Improved Matrix II
Tonight or tomorrow. I unfortunately can't say which affair is the most important
Per aspera ad astra.
Please post questions always in the forum and do not message them to me!
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| 12.03.2008 23:41 |
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Sheep
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Puristan
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RE: Improved Matrix II
Yes indeed. I did not yet work it out completely, so the  will get rewarded for sparing me some work 
Thanks.
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| 13.03.2008 00:40 |
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F.N. Babeuf
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Bayern Westfalen
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RE: Improved Matrix II
anscheinend ist ja jetzt die neue matrix aktiv.
aber mit der formel von sheep komme ich, wenn ALPS eine bündnis stärke von 9,99 hat, bei NADO auf 9,00 und nicht 9,93.
Mir fällt auch keine Umrechnung ein, bei der aus dem verhältnis 42/30 das verhältnis 9,99/9,93 wird...
gibt es dafür eine erklärung oder müssen die spieler das so hinnehmen?
/edit:
sorry!
the new matrix is obviously active.
but according to the sheep's formula the ally-strenght of NADO has to be 9,00 and not 9,93 if ALPS has 9,99.
I cannot remember a conversion changing the proportion 42/30 into 9,99/9,00...
are the players forced to accept this without explanation?
This post was last modified: 19.03.2008 20:48 by F.N. Babeuf.
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| 19.03.2008 19:52 |
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Bertrams
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Orbitanien Seewald Terrania
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RE: Improved Matrix II
Please post english in this thread!
Das Radio, das Brücken baut und an dem ich beteiligt bin - www.ohrfunk.de
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| 19.03.2008 20:20 |
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Malone
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Joyland Malonatia Prosperia
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RE: Improved Matrix II
anscheinend ist ja jetzt die neue matrix aktiv.
aber mit der formel von sheep komme ich, wenn ALPS eine bündnis stärke von 9,99 hat, bei NADO auf 9,00 und nicht 9,93.
Mir fällt auch keine Umrechnung ein, bei der aus dem verhältnis 42/30 das verhältnis 9,99/9,93 wird...
gibt es dafür eine erklärung oder müssen die spieler das so hinnehmen?
/edit:
sorry!
the new matrix is obviously active.
but according to the sheep's formula the ally-strenght of NADO has to be 9,00 and not 9,93 if ALPS has 9,99.
I cannot remember a conversion changing the proportion 42/30 into 9,99/9,00...
are the players forced to accept this without explanation?
Cleared. We just for the display the parameters 10 and 0,2
Per aspera ad astra.
Please post questions always in the forum and do not message them to me!
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| 19.03.2008 21:53 |
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